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Y = x 2 2x – 5;To be tangent it has to cross the curve in only one place so, the intersection between the two of them need to cross in just one place and should not pass for the vertice vertically (that will be an exception buy easy to notice) in this case y=#1 Report Thread starter 1 year


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Substitute 1 for a, 2 for b, and 6y for c in the quadratic formula, \frac{b±\sqrt{b^{2}4ac}}{2a} This equation is in standard form a x 2 b x c = 0 Substitute 1 for a, 2 for b, and 6 − y for c in the quadratic formula, 2 a − b ± b 2 − 4 a c x=\frac{2±\sqrt{2^{2}4\left(6y\right)}}{2} x = 2 − 2 ± 2 2 − 4 (6 − y) Square 2 Square 2 x=\frac{2±\sqrt{44\left(6yTopics Terms and topics;Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more


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Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreSolved by pluggable solver Solve the System of Equations by Graphing Start with the given system of equations In order to graph these equations, we need to solve for y for each equation So let's solve for y on the first equationQuestion Graph the parabola y=2x^24x6 on graph paper Answer by ewatrrr() (Show Source) You can put


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